# trig

solve the equation on the interval [0, 2pi]:
tan^2 x - 3 tan x + 2 = 0

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1. (tanx - 1)(tanx - 2) = 0
tanx = 1 or tanx = 2

for tanx = 1,
x = π/4 or π+π/4 = 5π/4

for tanx = 2
x = appr 1.107 or π+1.107 = 4.249

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posted by Reiny

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