# Chem

Determine the volume of 0.250M KOH solution required to neutralize each of the following samples of sulfuric acid. 200mL of 0.135M H2SO4. I have gotten both 0.027 and 0.675. I thought it was mol/L. Please help!

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asked by JR
1. Use the following relationship:

M1V1=M2V2

Where

M1=0.250M
V1=?
M2=0.135M
and
V2=200mL

Solve for V1:

V1=(M2/M1)*V2

This would be the volume if the mole ratio were a 1 mole to 1 mole ratio. However, you need two moles of KOH for 1 mole of H2SO4:

Multiply V1 by 2 to arrive at the answer.

Answer should contain three significant figures.

And no, the answer will be in mL, since it is asking you for volume.

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posted by Devron

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