You randomly choose a natural number from 1-10. what is the probability that you choose a multiple of 2 or 3?
7/10
To find the probability of choosing a multiple of 2 or 3 from the numbers 1-10, we need to find the number of favorable outcomes and the total number of possible outcomes.
Multiples of 2 from 1-10: 2, 4, 6, 8, 10
Multiples of 3 from 1-10: 3, 6, 9
The numbers that are multiples of 2 or 3 are: 2, 3, 4, 6, 8, 9, 10.
So, the favorable outcomes are 7.
The total number of possible outcomes is 10, as we are choosing from the numbers 1-10.
Therefore, the probability of choosing a multiple of 2 or 3 is given by the formula:
Probability = Favorable outcomes / Total outcomes = 7/10 = 0.7
So, the probability that you randomly choose a multiple of 2 or 3 is 0.7 or 70%.
To determine the probability of choosing a multiple of 2 or 3 from the numbers 1-10, we need to find the number of favorable outcomes and divide it by the total number of possible outcomes.
Step 1: Determine the favorable outcomes.
The multiples of 2 in the range 1-10 are: 2, 4, 6, 8, 10
The multiples of 3 in the range 1-10 are: 3, 6, 9
To find the total number of favorable outcomes, we need to count the unique multiples. Therefore, the favorable outcomes are 2, 3, 4, 6, 8, 9, 10.
Step 2: Determine the total number of possible outcomes.
The range of numbers is 1-10, so we have a total of 10 possible outcomes.
Step 3: Calculate the probability.
To find the probability, divide the number of favorable outcomes by the total number of possible outcomes:
Probability = (Number of favorable outcomes) / (Total number of possible outcomes)
= 7 / 10
= 0.7 or 70%
Therefore, the probability of randomly choosing a multiple of 2 or 3 from the numbers 1-10 is 0.7 or 70%.