# ALGEBRA

Multiply: (K+3)/(4K-2)*(12K^2 + 2k – 4)
• 3(k+3)/(3k+2)
• 3(k+3)(2k-1)/2
• (x-5)(3x+2)
• (x-5)(12x+8)

How?
11

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asked by Sandra
1. well, 12k^2+2k-4 = 2(3k+2)(2k-1)

so, we have

(k+3)/2(2k-1) * 2(3k+2)(2k-1)
now the 2(2k-1) cancels, leaving

(k+3)(3k+2)
No idea about the 11.

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posted by Steve

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