A truck has 5.9L engine in it. 5.9L of the overall displacement in 6 cylinders each 102mm bore (diameter) and 120mm stroke (length). Engine operates at 16.3:1 compression ratio and with 6psi (0.41atm) of boost cruising at 1600rpm.
What is the volume of ONE cylinder? Then add 6% to account for combustion chamber in the cylinder head.
What i've got to far is this:
V= pie*r^2*h
V= 3.14*51^2*120= 19,216.8mm
19,216.8mm*.06= 1,153.008
19,216.8mm+1,153.008= 20, 369.808mm^3
Am i even close? Thanks
Your work is correct, but probably made some mistake with the calculator.
Volume = πr²h*1.06
= π(51)^2(120)×1.06;
=330847.2π
=1039387.133 mm³ approximately.
To find the volume of one cylinder, you've correctly used the formula for the volume of a cylinder (V = πr^2h), but there is a small error in your calculations. Let's go through the steps again to calculate the correct volume of one cylinder.
Given information:
- Bore (diameter) of each cylinder = 102mm
- Stroke (length) of each cylinder = 120mm
First, we need to convert the bore into the radius by dividing it by 2:
Bore / 2 = radius
102mm / 2 = 51mm
Now, we can substitute the values into the volume formula:
V = πr^2h
V = π * 51^2 * 120
V ≈ 973,473 mm^3
Next, to account for the combustion chamber in the cylinder head, we need to add 6% to the volume of one cylinder. To calculate this, we'll multiply the volume by 1.06:
Adjusted Volume = V * 1.06
Adjusted Volume ≈ 973,473 mm^3 * 1.06
Adjusted Volume ≈ 1,031,997.38 mm^3
So, the correct volume of one cylinder, including the combustion chamber, is approximately 1,031,997.38 mm^3.