Calculus/Physics

It took 1800J of work to stretch a spring from its natural length of 2m to a length of 5m. Find the spring's force constant.

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asked by Tim
  1. W = F*d = F * (5-2) = 1800 Joules.
    3F = 1800
    F = 600 N.

    k = 600N./3m = 200N/m

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    posted by Henry

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