calculus help

find the derivative of the function


integral from cosx to sinx (ln(8+3v)dv)

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asked by Chris
  1. the derivative of a definite integral is how much the area changes as you change the limits.

    d/dx Int from p(x) to q(x) of f(v)dv
    = [f(q)-f(p)]dx

    (draw a sketch of that graph)

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    posted by Damon
  2. sorry, extra dx in there
    = f(q) - f(p)

    f(q) = ln (8+3sin x)
    f(p) = ln (8+3cos x)

    f(q)-f(p) = ln [ (8+3sin x)/(8+3cos x) ]

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    posted by Damon
  3. y'(x)= (sin(8+3((sin(x)))+x)+sin(8+3sin(x)-x))/2

    Is this the right answer?????

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    posted by Chris
  4. Well, I gave you my answer which is quite different.

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    posted by Damon

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