how much energy is needed to change 53 grams of water from -53 degrees celsius to 160 degrees celsius ?
To calculate the amount of energy needed to change the temperature of a substance, we can use the formula:
Q = m * C * ΔT
Where:
Q is the amount of energy (in joules),
m is the mass of the substance (in grams),
C is the specific heat capacity of the substance (in joules per gram per degree Celsius), and
ΔT is the change in temperature (in degrees Celsius).
In this case, we need to find the energy required to change the temperature of 53 grams of water from -53 degrees Celsius to 160 degrees Celsius.
First, let's calculate the energy required to heat the water from -53 degrees Celsius to 0 degrees Celsius:
Q1 = m * C * ΔT1
Here, the mass m is 53 grams, the specific heat capacity C for water is 4.18 J/g°C, and the change in temperature ΔT1 is (0 - (-53)) = 53 degrees Celsius.
Q1 = 53 g * 4.18 J/g°C * 53°C
Next, let's calculate the energy required to heat the water from 0 degrees Celsius to 100 degrees Celsius (boiling point):
Q2 = m * C * ΔT2
Here, the mass m is still 53 grams, the specific heat capacity C remains 4.18 J/g°C, and the change in temperature ΔT2 is (100 - 0) = 100 degrees Celsius.
Q2 = 53 g * 4.18 J/g°C * 100°C
Finally, let's calculate the energy required to heat the water from 100 degrees Celsius to 160 degrees Celsius:
Q3 = m * C * ΔT3
Using the same values as before, but with a change in temperature ΔT3 of (160 - 100) = 60 degrees Celsius.
Q3 = 53 g * 4.18 J/g°C * 60°C
To find the total energy required, we add up the three amounts of energy:
Total energy = Q1 + Q2 + Q3
After performing the calculations, you will get the total energy needed to change 53 grams of water from -53 degrees Celsius to 160 degrees Celsius.
To calculate the energy needed to change the temperature of a substance, you can use the specific heat capacity formula. The specific heat capacity of water is approximately 4.18 J/g°C.
The energy required can be calculated using the formula:
Q = m * c * ΔT
Where:
Q = Energy (in Joules)
m = Mass of water (in grams)
c = Specific heat capacity of water (in J/g°C)
ΔT = Change in temperature (in °C)
Given:
Mass of water (m) = 53 grams
Specific heat capacity of water (c) = 4.18 J/g°C
Change in temperature (ΔT) = 160°C - (-53°C) = 160°C + 53°C = 213°C
Substituting the values:
Q = 53 * 4.18 * 213
Q ≈ 47,568.18 Joules
Therefore, approximately 47,568.18 Joules of energy are needed to change 53 grams of water from -53 degrees Celsius to 160 degrees Celsius.