jan goes 6 kilometers east from home. mell goes 8kilometers north. how many kilometers are there schools apart. use Pythagorean theorem
6^2 + 8^2 = k^2
36 + 64 = k^2
100 = k^2
10 = k
thanks ms sue
You're welcome, Lal.
To find the distance between the two schools using the Pythagorean theorem, we need to consider the distances traveled by Jan and Mell as the legs of a right triangle.
Let's start by drawing a diagram to visualize the situation. Assume that Jan's starting point is at the origin (0, 0) on a Cartesian coordinate system.
Jan travels 6 kilometers east, which means his location is now at (6, 0). Mell, on the other hand, goes 8 kilometers north, so her position is at (0, 8).
Now, we can see that Jan and Mell's positions form a right triangle. The distance between the two schools is the length of the hypotenuse of this triangle.
Using the Pythagorean theorem, which states that the square of the length of the hypotenuse (c) is equal to the sum of the squares of the lengths of the other two sides (a and b), we can calculate the distance between the two schools.
In this case, the length of side a is 6 kilometers (the horizontal distance traveled by Jan), and the length of side b is 8 kilometers (the vertical distance traveled by Mell).
So, substituting the values into the formula:
c² = a² + b²
c² = 6² + 8²
Simplifying:
c² = 36 + 64
c² = 100
Taking the square root of both sides to find the value of c:
c = √100
c = 10
Therefore, the distance between the two schools is 10 kilometers.