CHEMISTRY HELP !!!!

Cell Designation : E (measured)
= Sn I Sn^2+ II Cu^2+ I Cu

Temp= 3 Celsius

Temp= 276.15 Kelvin

Delta G= ?????

Show work please!!!!

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  1. I have to use the formula below but I don't know how! :(

    Delta G = -nFE

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  2. n = number of electrons transferred. In this case that is 2. Sn ==> Sn^2+ + 2e and Cu^2+ + 2e ==> Cu
    F is the Faraday constant of 95,485 coulombs
    E is the cell voltage.
    T is kelvin temperature. substitute and go. Don't foget the - sign.

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  3. how do i get voltage cell????

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  4. Your post said "E measured" so I assume you have that given to you. If it isn't given, add the oxidation half cell to the reduction half cell to obtain Ecell.

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