A cylinder with a movable piston has the square meter 24cm2. How far will the piston go down if 5.0 kg weight is laid on the piston and the temperature remains the same?
P: 1.0 atm.

Help please :)

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  1. I do not know V, the initial Volume of gas so can not do the problemP V = n R T

    P dV + V dP = 0 if n R and T do not change

    P initial = 10^5 Newtons/m^2 ( or Pacals)

    dV = (24*10^-4) x

    V = I have no idea. You left this out.

    dP = 5*9.81/(24*10^-4)

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