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Find the 6th term of the arithmetic sequence with a9=120 and a14=195

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  1. a9 = 120 ----> a + 8d = 120
    a14 = 195 ---> a + 13d = 195
    subtract them
    5d = 75
    d = 15
    then a+8(15) = 120
    a = 0

    so term(6) = a+5d = 0 + 5(15) = 75

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  2. find the 6th term of an arithmetic sequence with a9 = 12 and a14 = 195

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