What is the molecular mass of a gas that diffuses through a porous membrane 1.86 times faster than Xe?

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  1. I would assume a convenient number for the rate of Xe, say something like 5 L/min. Then rate unknown gas, x, is 1.86*5.
    (rate x/rate Xe) = (MM Xe/MM X)
    Solve for MM = molar mass X.

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