Calculus

Let f(x) = sqrt(3x+15)

Find f'(x)

The answer is 3/(2sqrt(3x+15)

Can anyone who does this please explain step by step why you did what you did? I have a lot of difficulty finding the derivative with radicals.

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  1. Instead of radical form, write the problem in exponential form.
    f(x)=(3x + 15)^(1/2)
    f'(x)=(1/2)((3x+15)^(1/2 - 1)) 3
    f'(x)=(3/2)(3x+15)^(-1/2)

    f'(x)=3/(2*(3x+15)^(1/2))

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