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calculus
find the volume of the solid formed by revolving the region bounded by the graphs of y=x^3,y=1, and x=2 about the xaxis using the disk method. 9 express the answer in terms of pie) i got the answer to be 3/5 pie but im not sure
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Find the volume of the solid generated by revolving the region bounded by the graphs of the equations about the xaxis. y = sin x, y = 0, x = 0 I just need help setting up the formula. So far I got V= the integral from 0 to pi of
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The motion of a particle is described by x = 10 sin (piet +pie/2 ). At what time ( in second ) is the potential energy equal to the kinetic energy ? here is what i have done so far where am i going wrong V=pie10cos(piet + pie/3)
asked by shan on December 12, 2007 
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Choose the two options which are true for all values of x 1) cos (x) = cos ( x – pie/2) 2) sin (x + pie/2) = cos (x – pie/2) 3) cos (x) = sin (x – pie/2) 4) sin (x) = sin (x + 4pie) 5) sin (x) = cos (x – pie/2) 6) sin^2
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Let R be the region bounded by the graphs of y=sin(pi x) and y=(x^3)4x, as shown in the figure above. (a) Find the area of R. (b) The horizontal line y=2, x=2, x=1. Write, but do not evaluate, an integral expression for the
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calculus
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sketch the region bounded by the graphs of f(y)=(y/Squareroot of(16y^2)), g(y)=0, y=3 and find the area of the region.
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