# Chemistry

How many mL of 0.49 M HCl will neutralize 42 mL of 1.48 M NaOH?

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1. HCl + NaOH ==> NaCl + H2O
mols NaOH = M x L = ?
mols HCl = mols NaOH (from the coefficients in the balanced equation.)
Then M HCl = mols HCl/L HCl. You know mols and M HCl, solve for L and convert to mL.

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2. so then you would take 1.48 M times 42mL, then take that number and divide by .49 M, then convert to mL?

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3. No, it's 1.48 M times 0.042 L and divide by 049, solve and convert to mL.

However, you can save some time if you do it this way.
1.42 x 42 mL and divide by 0.49. That gives the answer in mL and there is no conversion to do.

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