1. Calculate the volume of carbon dioxide at 273 K and 1.01 * 10^5 Pa which would be produced when 1.25g of calcium carbonate reacts completely with HCL.
and
2. When 41.18 cm^3 of a solution of silver ions with concentration of .2040 mol dm^-3 is added to a solution of XO4 -3 ions 1.172g of precipitate are formed.
i) calculate the amount in moles of Ag+ used in the reaction.
ii)Calculate molar mass of precipitate
iii)Determine the relative atomic mass of X and identify the element.
thanks for the help even if you can't answer it! thanks!
1. To calculate the volume of carbon dioxide produced, we need to use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.
First, we need to calculate the number of moles of CO2 produced. The balanced equation for the reaction between calcium carbonate and HCl is:
CaCO3 + 2HCl -> CO2 + CaCl2 + H2O
From the equation, we can see that 1 mole of CaCO3 produces 1 mole of CO2. The molar mass of CaCO3 is 100.09 g/mol, so 1.25 g of CaCO3 is equal to (1.25 g) / (100.09 g/mol) = 0.01249 mol.
Next, we can substitute the known values into the ideal gas law equation to calculate the volume of CO2:
V = (nRT) / P
V = (0.01249 mol)(8.314 J/(mol·K))(273 K) / (1.01 * 10^5 Pa)
After performing the calculation, you will get the result for the volume of carbon dioxide produced.
2.
i) To calculate the amount in moles of Ag+ used in the reaction, we need to use the concentration and volume of the solution.
Given:
- Concentration of silver ions solution = 0.2040 mol/dm^3
- Volume of silver ions solution = 41.18 cm^3 = 41.18 * 10^-3 dm^3
The amount of Ag+ used can be calculated using the formula:
Amount (in moles) = Concentration × Volume
Amount (in moles) = 0.2040 mol/dm^3 × 41.18 * 10^-3 dm^3
After performing the calculation, you will get the amount in moles of Ag+ used in the reaction.
ii) To calculate the molar mass of the precipitate, we need to use the mass and the amount in moles of the precipitate formed.
Given:
- Mass of precipitate = 1.172 g
- Amount of precipitate (in moles) = calculated in part (ii)
The molar mass can be calculated using the formula:
Molar Mass = Mass / Amount (in moles)
Molar Mass = 1.172 g / calculated amount (in moles)
After performing the calculation, you will obtain the molar mass of the precipitate.
iii) To determine the relative atomic mass of X and identify the element, we need to use the molar mass of the precipitate and compare it to the atomic masses of the elements.
By comparing the molar mass of the precipitate to the atomic masses of elements, you can identify the element X based on the closest match. Look up the atomic masses and find the element that has a similar molar mass to the calculated molar mass of the precipitate.
Note: Without the specific molar mass value of the precipitate in your question, it is not possible to provide the exact element or its relative atomic mass.