physics

Please help me !!! for solution of this question
Water enters a horizontal pipe with a rectangular cross section at a speed of 1.00 m/s. The width of the pipe remains constant but the height decreases. 27.3 m from the entrance, the height is half of what it is at the entrance. If the water pressure at the entrance is 2921 Pa, what is the pressure 27.3 m downstream?

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  1. half the area is twice the speed

    V1 = 1 m/s
    V2 = 2 m/s
    Bernoulli
    (1/2) rho V1^2+P1 = (1/2) rho V2^2+P2
    rho water =1000 kg/m^3

    2921 Pa is very low by the way, like 1 atm = 100,000 Pa for example. Perhaps they mean gage pressure.

    500 (1)^2 + 2921 = 500 (2)^2 + P2
    2921 - P2 = 1500
    P2 = 1421 Pa

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  2. very thanks

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  3. You are welcome :)

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