A bag has 4 red marbles, 4 blue marbles, and 2 green marbles. Jessie draws a marble from the bag at random, notes the color, and then replaces the marble.She then draws a second marble at random.What is the probability that both the marbles are green?
a. 1/45
b. 1/25
c. 1/5
d. 2/5
please answer and explain
2 greens out of 10 marbles, so: (B)
yes, it's 1/5 for each marble. So, the chance of getting BOTH greens is 1/5 * 1/5 = 1/25
To find the probability that both the marbles drawn are green, we need to consider the total number of possible outcomes and the number of favorable outcomes.
First, let's determine the total number of possible outcomes. Since Jessie replaces the marble after each draw, the number of marbles in the bag remains the same for both draws. Therefore, the total number of marbles to choose from for each draw is 4 (red) + 4 (blue) + 2 (green) = 10.
Now, let's determine the number of favorable outcomes, which is the number of times both green marbles are drawn. There are 2 green marbles in the bag, so the number of favorable outcomes is 2.
The probability of an event is given by the equation:
probability = favorable outcomes / total outcomes
In this case, the probability is 2 (favorable outcomes) / 10 (total outcomes). Simplifying this fraction, we get 1/5.
Therefore, the correct answer is c. 1/5, since the probability that both marbles drawn are green is 1/5.
I don't understand . why answer b
2/10 = 1/5