# calculus help

find y' and y'' for the equation below.

y= (x^3)/((x+1)^2)

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1. https://www.wolframalpha.com/input/?i=derivative+of+%28x^3%29%2F%28%28x%2B1%29^2%29+

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2. [(x+1)^2 (3 x^2)-x^3 (2)(x+1)] /(x+1)^4

[(x+1)(3x^2) - 2 x^3 ]/ (x+1)^3

[ 3 x^3 + 3 x^2 -2 x^3 ] / (x+1)^3

[ x^3 + 3 x^2] /(x+1)^3

x^2 (x+3) / (x+1)^3

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3. then do it again :)

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