chemistry-stoichiometry

how many grams of chlorine can be liberated from the decomposition of 64.0g of AuCl3 by this reaction
2 AuCl3----> 2 Au + 3cl2

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  3. 👁 916
  1. All you need to do is convert to moles AuCL3 and then use the mole ratio and convert back to grams Cl2

    64.0*(1 mol/233g)*(3 mol Cl2/2mol AuCl3)*70.906gCl2=

    29.214

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  2. wrong

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