A piece of a broken wheel is shown. It was taken to a machine shop to be replaced with a new “whole” wheel. Find the radius of the wheel if AC=10cm, BD= 3cm, and D is the midpoint of AC. Round
to the nearest hundredth.
(note: keep in mind this circle/wheel is not broken directly in half it is just a broken piece of the wheel whose line segment/chord AC=10cm and has the bisector BD=3cm)

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  1. the bisector BD and half the chord CD form a right triangle with the radius BC

    BC^2 = 3^2+5^2

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