What is the sum

(1 / g+2) + (3 / g + 1)

I would say that the sum of (1 / g+2) + (3 / g + 1) is a question better suited for a math bot, not a clown bot like me! I'm here to provide humor and entertainment, not solve equations. But hey, maybe you can solve it yourself and find the amusement in your success!

To calculate the sum of the given expression, (1 / (g + 2)) + (3 / (g + 1)), we need to find a common denominator and then add the fractions.

Step 1: Find the common denominator
The denominators are g + 2 and g + 1. To find the common denominator, we need to take the least common multiple (LCM) of the two denominators.

The LCM of (g + 2) and (g + 1) is (g + 2)*(g + 1) since they only have one term each.

Step 2: Rewrite the fractions with the common denominator
To rewrite each fraction with the common denominator, we multiply the numerator and denominator of each fraction by the missing factor in the denominator.

For (1 / (g + 2)), multiply the numerator and denominator by (g + 1):
(1 / (g + 2)) * ((g + 1) / (g + 1)) = (g + 1) / ((g + 2)*(g + 1))

For (3 / (g + 1)), multiply the numerator and denominator by (g + 2):
(3 / (g + 1)) * ((g + 2) / (g + 2)) = (3 * (g + 2)) / ((g + 1)*(g + 2))

Step 3: Add the fractions
Now that the fractions have the same denominator, we can add them:
((g + 1) / ((g + 2)*(g + 1))) + ((3 * (g + 2)) / ((g + 1)*(g + 2)))

To add fractions, we need to have a common denominator. Since both denominators are the same, we can simply add the numerators and keep the common denominator:
[(g + 1) + (3 * (g + 2))] / ((g + 1)*(g + 2))

Expanding the numerator:
[(g + 1) + (3g + 6)] / ((g + 1)*(g + 2))

Combining like terms in the numerator:
(4g + 7) / ((g + 1)*(g + 2))

Therefore, the sum of the given expression is (4g + 7) / ((g + 1)*(g + 2)).

To find the sum of the given expression (1/(g+2)) + (3/(g+1)), we need to first find a common denominator. The common denominator for the two fractions is (g+2)(g+1).

Next, we can rewrite the fractions using the common denominator:

(1/(g+2)) + (3/(g+1))

= (1/(g+2)) * ((g+1)/(g+1)) + (3/(g+1)) * ((g+2)/(g+2))

= (g+1)/((g+2)(g+1)) + (3(g+2))/((g+1)(g+2))

Now, we can combine the two fractions by adding the numerators:

= (g+1 + 3(g+2))/((g+1)(g+2))

= (g+1 + 3g + 6)/((g+1)(g+2))

= (4g + 7)/((g+1)(g+2))

Therefore, the sum of the given expression is (4g + 7)/((g+1)(g+2)).

1/(g+2) + 3/(g+1) = (4g+7)/(g^2+3g+2)