If equal amounts of heat are added to equal masses of silver and copper, both at the same initial temperature, which will reach the higher final temperature? Explain your answer. The specific heat capacity of silver is 0.235 J/g degree Celsius and that of copper is 0.385 J/g degree Celsius.

If equal amounts of heat are added to equal masses of silver and copper, both at the same initial temperature, which will reach the higher final temperature? Explain your answer. The specific heat capacity of silver is 0.235 J/g·oC and that of copper is 0.385 J/g·°C.

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Well, silver may be known for its shine, but when it comes to reaching higher temperatures, copper gives it a run for its money!

Here's the explanation behind it: The specific heat capacity is a measure of how much heat energy is required to raise the temperature of a substance by one degree Celsius per gram. Since copper has a higher specific heat capacity of 0.385 J/g degree Celsius compared to silver's 0.235 J/g degree Celsius, it means that copper needs more energy to heat up per gram than silver.

So, when equal amounts of heat energy are added to equal masses of silver and copper, copper will require more of that heat energy to raise its temperature than silver. As a result, copper will reach a higher final temperature compared to silver.

In simpler terms, copper likes to hog more heat energy than silver, making it the temperature champ in this scenario. Hope that clears things up!

To determine which metal will reach a higher final temperature when equal amounts of heat are added, we need to consider the specific heat capacity of each metal.

The specific heat capacity (C) of a substance is the amount of heat energy required to raise the temperature of one gram of the substance by one degree Celsius.

In this case, we have a mass of silver and copper that are equal in weight and are initially at the same temperature. Let's assume the mass of both metals is "m" grams.

The heat energy (Q) required to raise the temperature of a substance can be calculated using the equation:

Q = m * C * ΔT

Where:
Q = heat energy (in joules)
m = mass of the substance (in grams)
C = specific heat capacity of the substance (in J/g °C)
ΔT = change in temperature (in °C)

Since we are adding equal amounts of heat energy to both silver and copper, the heat energy added (Q) will be the same for both metals.

Since Q is the same, we can rearrange the equation to compare the change in temperature (ΔT) for each metal:

ΔT = Q / (m * C)

From this equation, we can see that the change in temperature is inversely proportional to the specific heat capacity of the metal. In other words, a substance with a higher specific heat capacity will have a lower change in temperature for the same amount of heat energy.

Comparing the specific heat capacities of silver and copper, we can see that copper has a higher value (0.385 J/g °C) compared to silver (0.235 J/g °C). Therefore, copper will have a lower change in temperature (ΔT) compared to silver for the same amount of heat energy.

Consequently, silver will reach a higher final temperature than copper when equal amounts of heat are added to equal masses of both metals, provided all other factors are constant.

In summary, the specific heat capacity of each metal determines how much the temperature of the metal changes when heat is added. The metal with a lower specific heat capacity, in this case, silver, will reach a higher final temperature compared to the metal with a higher specific heat capacity, copper, when equal amounts of heat are added.

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q = mass metal x specific heat metal x (Tfinal-Tinitial)

An easy way to do this is to assign some convenient number for q, give it some convenient starting T and solve for Tfinal.

Or you can reason it out. If sp.h. Ag is 0.235 and that of Cu is 0.385 then it takes more heat to heat Cu than Ag to the same temperature.

or still another way.
q = mass Ag x 0.235 x delta T
q = mass Cu x 0.385 x delta T.
But mass is same so for Ag
delta T = q/0.235 and for Cu
delta T = q/0.385
So for same q, the smaller denominator gives a greater delta T.