A and B are positive acute angles. if sin A=4/5 and cos B=8/17 find the value of tan (A-B)

is the answer =43/100

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  1. cosA = 3/5
    sinB = 15/17

    tanA = 4/3
    tanB = 15/8

    tan(A-B) = (tanA-tanB)/(1+tanAtanB)
    = (4/3 - 15/8)/(1+(4/3)(15/8))
    = (-13/24)/(7/2)
    = -13/84

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  2. thanks

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