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5x^4-41x^3-87x^2-31x+10=0

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  1. I assume you want values of x which solve the equation.

    Well, you know the rational roots will be of the form 1,2,5,10 or 1/5,2/5

    A little synthetic division shows that x+1 divides twice, so you have

    (x+1)(x+1)(5x^2-51x+10)

    Now you can easily see that it is

    (x+1)(x+1)(x-10)(5x-1) = 0

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