You take a trip by air that involves three independent flights. If there is an 67% chance each specific leg of the trip is on time, what is the probability all three flights arrive on time? (Round your answer to 3 decimal places.)

Probability =??

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  1. P(all) = 3C3 (.67)^3(.33)^0 = 300763

    Answer is 0.301

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  2. Typo

    P(all) = 3C3 (.67)^3(.33)^0 =0. 300763

    Answer is 0.301

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