A physics student stands at the top of hill that has an elevation of 37 meters. He throws a rock and it goes up into the air and then falls back past him and lands on the ground below. The path of the rock can be modeled by the equation y = –0.02x² + 0.8x + 37 where x is the horizontal distance, in meters, from the starting point on the top of the hill and y is the height, in meters, of the rock above the ground. How far horizontally from its starting point will the rock land? Round your answer to the nearest hundredth.

Thank you so much Henry, God Bless

Use Quadratic Formula:

X = (-0.8 +- sqrt(0.64+2.96))/-0.04 =
-27.43, and 67.43

X = 67.43 m.

^^ none of those are right

bro whos right

Does anyone know the answers to the Unit 5 Lesson 10 quiz?

is lee right????????

all those answers are the opposite of the ones I guarantee I did correctly. Don't use them

oh J, sorry to reply so late, but then may i ask what your answers were? I'd reallyyyy hate to lead anyone wrong (though I didn't)

:*

tested changed

are these right

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