# Calculus

Determine whether the series is convergent or divergent. If it is convergent, find its sum. If it is divergent, enter NONE.
sum from 1 to infinity of 1/e^2n.
It is convergent, but I do not know how to solve for the sum.

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1. sure you do. It's just a geometric series

a = 1/e^2
r = 1/e^2

S = a/1-r = (1/e^2)/(1 - 1/e^2) = 1/(e^2-1)

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