# Algebra II

Suppose that an object is dropped from a height of h meters and hits the ground with a velocity of v meters per second. Then v= sqrt19.6h. If an object hits the ground with a velocity of 24.2 meters per second, from what height was it dropped?

Carry your intermediate computations to at least four decimal places, and round your answer to the nearest tenth.

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1. just plug in your value:
24.2 = √(19.6 h)
√h = 24.2/√19.6
h = (24.2/√19.6)^2 = 29.88 m

or

I know from physics that
h = 4.905 t^2 gives you the height from which an object was dropped after t seconds ,
and v = 9.81 t gives you the velocity after t seconds

so 24.2 = 9.81 t
t = 2.46687..
h = 4.905(2.46687..)^2= appr 29.85 m

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2. If your rounding to the nearent tenth though that can't plug in. I'm so confused.

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3. The answer is 32.1 meters

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