Chem 2 help

At a certain temperature, 0.800 mol of SO3 is placed in a 2.00-L container.
2so3<->2so2 +o2

At equilibrium, 0.140 mol of O2 is present. Calculate Kc.

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  1. 0.800 mol/2.00L = 0.400M
    ........2SO3 <==> 2SO2 + O2
    I.....0.400M........0.....0
    C.......-2x........2x.....x
    E.....0400-2x......2x.....x

    x = O2 = 0.140mol/2.00L = 0.07M
    Then 2x = 0.140M = (SO2)
    and 0.400-0.140 = 0.26M = (SO3)

    Substitute these into the Kc expression and solve for Kc.

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