physics

modern oil tankers weigh more than a half-million tons and have lengths of up to one-fourth mile. Such massive ships require a distance of 5.0 km (about 3.0 mi) and a time of 20 min to come to a stop from a top speed of 30 km/h.

What is the magnitude of a such a ship's average acceleration in m/s^2 in coming to a stop?

what is the magnitude of the ships average velocity in m/s?

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  1. 5000 meters in 20*60 = 1200 seconds

    Vi = 30,000 m / 3600 s = 83.3 m/s

    v = Vi + a t
    0 = 83.3 + a (1200)
    a = - .0694 = - 6.94 * 10^-2 m/s^2

    average velocity with constant acceleration = (first + last)/2
    = 83.3/2 = 41.7 m/s

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  2. why is it not 30-0/20=1.5

    and

    5/20=4 km/min = 4,000 m/min = 66.67 m/s?

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  3. 5/20=4 km/min = 4,000 m/min = 66.67 m/s?
    BECAUSE
    5/20 = 1/4 not 4

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  4. Where did you get 3600 seconds?

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  5. I figured it out. 3600 seconds in an hour.

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