math

A model rocket is launched from a roof into a large field. The path of the rocket can be modeled by the equation y = -0.06x^2 + 9.6x + 5.4 where x is the horizontal distance, in meters from the starting point on the roof and y is the height in meters of the rocket above the ground how far horizontally from its starting point will the rocket land?/ round your answer to the nearest hundredth
4.30 m
160.56 m
160.23 m
13.94 m

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asked by nisa
  1. find the zeros of that parabola, use the + one
    (I turned the parabola upside down because I like positive x^2 term)

    .06 x^2 - 9.6 x - 5.4 = 0

    use x = [-b +/- sqrt(b^2-4ac) ]/2a

    while I use wolfram alpha

    http://www.wolframalpha.com/input/?i=+.06+x^2+-+9.6+x+-+5.4+%3D+0++

    to get 160.56

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    posted by Damon

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