# Calc or Pre calc

I am having trouble doing this problem. I know how to do indefinate integrals, but I don't know how to do definate integrals. Can you show me how to do this.

Evaluate
5
(x^3-2x)dx
2

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1. To get the definite integral subtract the value of the indefinite integral at x=2 from the value at x=5. The arbitrary cnstant c will cancel out.
The indefinite integral is x^4/4 - x^2 + C.

The definite integral is
(625/4) - 25 -[16/4 - 4].

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