How to simplify
4sin[pi/2 + x] ?
using
sin(A+B) = sinAcosB + cosAsinB
4sin(π/2+x)
= 4(sin(π/2)cosx + cos(π/2)sinx)
= 4( (1)cosx + (0)sinx)
= 4 cosx
Thank you!
To simplify the expression 4sin[pi/2 + x], we can make use of the trigonometric identities. Specifically, the identity sin(a + b) = sin(a)cos(b) + cos(a)sin(b).
Let's apply this identity to the given expression:
4sin[pi/2 + x] = 4(sin(pi/2)cos(x) + cos(pi/2)sin(x))
Since sin(pi/2) equals 1 and cos(pi/2) equals 0, the expression simplifies to:
4(1cos(x) + 0sin(x)) = 4cos(x)
Therefore, the simplified form of 4sin[pi/2 + x] is 4cos(x).