maths

differentiate y = tan^2(3x) + sec^2(3x)

  1. 👍 0
  2. 👎 0
  3. 👁 119
asked by sean
  1. Use the chain rule separately for each of the two terms. The first term can be differentiated as follows:

    Let u = tan 3x and v = u^2
    tan^2(3x) = v{u(x)}

    d/dx [tan^2(3x)] = (dv/du)*(du/dx)
    = 2u * 3 sec^2 3x
    = 6 tan(3x)*sec^2(3x)

    Use a similar procedure to differentiate sec^2(3x)

    1. 👍 0
    2. 👎 0
    posted by drwls

Respond to this Question

First Name

Your Response

Similar Questions

  1. Integration

    Intergrate ¡ì sec^3(x) dx could anybody please check this answer. are the steps correct? thanks. = ¡ì sec x d tan x = sec x tan x - ¡ì tan x d sec x = sec x tan x - ¡ì sec x tan^2(x) dx = sec x tan x + ¡ì sec x dx - ¡ì

    asked by Vidal on October 15, 2006
  2. calculus (check my work please)

    Not sure if it is right, I have check with the answer in the book and a few integral calculators but they seem to get a different answer ∫ sec^3(x)tan^3(x) dx ∫ sec^3(x)tan(x)(sec^2(x)-1) dx ∫ tan(x)sec(x)[sec^4(x)-sec^2(x)]

    asked by Jay on June 7, 2012
  3. Calculus 12th grade (double check my work please)

    2- given the curve is described by the equation r=3cos ¥è, find the angle that the tangent line makes with the radius vector when ¥è=120¨¬. A. 30¨¬ B. 45¨¬ C. 60¨¬ D. 90¨¬ not sure A or D 2.) which of the following

    asked by anon on March 6, 2011
  4. calculus

    find dy/dx y=ln (secx + tanx) Let u= secx + tan x dy/dx= 1/u * du/dx now, put the derivative of d secx/dx + dtanx/dx in. You may have some challenging algebra to simplify it. Use the chain rule. Let y(u) = ln u u(x) = sec x + tan

    asked by amy on March 9, 2007
  5. Calculus AP

    I'm doing trigonometric integrals i wanted to know im doing step is my answer right? ∫ tan^3 (2x) sec^5(2x) dx =∫ tan^2(2x) sec^4(2x) tan*sec(2x) dx =∫ (sec^2(2x)-1)sec^4 tan*sec(2x) dx let u=sec x, du= 1/2 tan*sec(2x) dx

    asked by Vicky on September 22, 2012
  6. calculus

    So I am suppose to evaulate this problem y=tan^4(2x) and I am confused. my friend did this : 3 tan ^4 (2x) d sec^ 2x (2x)= 6 tan ^4 (2x) d sec^2 (2x) She says it's right but what confuses me is she deriving the 4 and made it a

    asked by Anonymous on July 28, 2012
  7. Calculus

    Differentiate to find critical numbers and leave function in fully factored form. g(x) = (x^2+1)^5(x^2+2)^6 g'(x) = (x^2+1)^5[6(x^2+2)^5(2x)] + (x^2+2)^6[5(x^2+1)^4(2x)] g'(x) = 2x(x^2+1)^4(x^2+2)^5[6(x^2+2)(2x) + 5(x^2+1)(2x)]

    asked by Justin on October 14, 2015
  8. Calculus

    could anybody please explain how sec x tan x - ¡ì sec x tan^2(x) dx = sec x tan x + ¡ì sec x dx - ¡ì sec^3(x) dx What I don't understand about your question is what is ¡ì ? i just want to know if those two equations are

    asked by Rain on October 16, 2006
  9. Math differentiation

    Can somebody please check these over for me? I really want to know what I did wrong if I made mistakes! Differentiate the following: 1. y = ln [(4-x)/(4+x)] Since it's the ln of the entire thing, then I can apply ln a - ln b so,

    asked by Marissa on August 26, 2008
  10. more trig.... how fun!!!!

    if you can't help me with my first question hopw you can help me with this one. sec(-x)/csc(-x)=tan(x) thanx to anyone who can help From the definition of the sec and csc functions, and the tan function, sec(-x)/csc(-x) =

    asked by berhana on November 6, 2006
  11. trigo help!

    1. differentiate cos(3/x) 2. differentiate sin(4/x) 3. differentiate 3/{sin(3x+pi)} 4. differentiate pxsin(q/x)where p and q are constants. 5. differentiate xsin(a/x) where a is constant 6. differentiate sec^3(3x^2+1)

    asked by I'm stumped on June 19, 2009

More Similar Questions