Chemistry

Manganese has the oxidation number of +5 in ______ . .
(A) [MnF6]3– (C) [MnO4]2–
(B) Mn2O7 (D) [Mn(CN)6]–

  1. 👍 0
  2. 👎 0
  3. 👁 167
asked by LT
  1. Take a.
    F is -1. 6 of them makes -6. We want to leave a -3 charge on the ion; therefore, Mn must be +3. +3 and -6 = +3.

    b. Mn2O7. O is -2. Seven of them makes -14.
    14/2 = +7 each for Mn. Check it. +14 for 2 Mn + (-14) for 7 O atoms = 0.

    c. MnO4^-. O is -2. Four of them make -8. We want to leave a -1 charge on the ion; therefore, Mn must be +7. Check it. +7 + (-8) = -1 charge on the ion.

    d. Mn(CN)6^-1.
    CN is -1, six of them makes -6. We want to leave a -1 charge on the ion; therefore, Mn must be +5.
    Check it. Mn = +5 + (-6 for CN) = -1 charge on the ion.

    1. 👍 0
    2. 👎 0

Respond to this Question

First Name

Your Response

Similar Questions

  1. Chem

    what occurs during the reaction below 4Hcl+MnO2-->MnCl2+2H2O+Cl2 1.the manganese is reduced and its oxidation number changes from +4 to +2. 2.the manganese is oxidized and its oxidation number changes from +4 to +2. 3.the

    asked by Tina on March 20, 2011
  2. Chemistry

    Electron Transfer Theory Write an label the oxidation and reduction half-reaction equations. a) Ni(s) + Cu(NO3)2(aq) -> Cu(s)+ Ni(No3)2(aq) oxidation - Ni(s) -> Ni2+(aq) + 2e- reduction - Cu2+(aq) + 2e- -> Cu(s) b) Pb(s) +

    asked by Alex on February 10, 2008
  3. Chemistry

    Electron Transfer Theory Write an label the oxidation and reduction half-reaction equations. a) Ni(s) + Cu(NO3)2(aq) -> Cu(s)+ Ni(No3)2(aq) oxidation - Ni(s) -> Ni2+(aq) + 2e- reduction - Cu2+(aq) + 2e- -> Cu(s) b) Pb(s) +

    asked by Alex on February 10, 2008
  4. Chemistry

    1. Tube # 3: (a) It started out as purple, and turned into green. (b) No precipitate was noticably formed. Tube #4: (a) This tube was purple, and turned into white. (b) A brown precipitate was formed after adding 1 mL of NaHSO3.

    asked by Miranda on March 28, 2012
  5. Chemistry - Please check

    d) 2Al(s) + Fe2O3(s)  2Fe(l) + Al2O3(s) Oxidation 2Al(s)  2Al+ + 2e- Reduction Fe23+ + 3e-  2Fe(l) Oxidation numbers for chlorine HCl = -1 MnO2(s)= +4 KMnO4(s)= +7 Oxidation numbers for manganese Mn(s)= ? MnCl2(s)= +7

    asked by Alex on February 13, 2008
  6. Chemistry

    Using the change in oxidation number method, balance the redox reaction shown below. (NO2^2)+ (MnO4^-)---> (NO3^-)+ Mn^2+ Divide into half reactions. I will show you how to do MnO4^- and you do the other one. MnO4^- ==> Mn^+2 Step

    asked by Aubrey on June 17, 2007
  7. analytical chemistry

    Write balanced net-ionic equations to describe: a. The oxidation of Mn2+ to MnO4- by ammonium peroxydisulfate [(NH4)2S2O8] b. The air-oxidation of HAsO32- to HAsO42- c. The oxidation of Ce3+ to Ce4+ by sodium bismuthate (NaBiO3)

    asked by Anonymous on February 14, 2013
  8. Chemistry

    1) Consider the following substance: V3N5. What is the oxidation number of vanadium and nitrogen? 2) Consider the following substance: Mn2O7. What is the oxadation number of manganese and oxygen? 3) Consider the following

    asked by Ryan on January 13, 2012
  9. Inorganic chemistry

    MnO4^-(aq) + H20(l) ==> MnO2 + OH^- net charg is -1 +7 (-8) ==> 4(-4) Manganese is reduced MnO4^- +3e- ==> MnO2 H2) is the oxidizing agent in a basic solution Mno4^- + H2O(l) --> MnO2(s) + OH^- Add on OH^- to both sides of the

    asked by Steve on April 14, 2009
  10. Chemistry - DrBob222

    CH3OH + MnO4- ----> Mn2+ + CH2O Earlier I posted this question and then realized that CH3OH didn't have a charge. It changed my work because the oxidation state changed. Can you check if what I fixed is correct? CH3OH- + MnO4-

    asked by Alex on February 20, 2008

More Similar Questions