When 6.724 g of one of the hydrates of sodium sulfate (Na2SO4) was heated to drive off its water of hydration, the residue of anhydrous sodium sulfate has a mass of 2.964 g. What is the value of x in the formula for the hydrate, Na2SO4•xH2O?
A 3.48 gram sample of sodium sulfate hydrate lost 1.35 gram of water when heated to constant weight. What is the formula of the hydrate? this is what I did, but I am stuck. Na2SO4 . H2O------> NA2SO4+H20
The sulfate in a 0.2345 g sample of a mixture containing only K2SO4 (fm = 174.26) and Na2SO4 (fm = 142.04) is to beanalyzed by precipitating all the sulfate as barium sulfate, BaSO4 (fm = 233.39) by the addition of excess BaCl2.
Aqueous sulfuric acid H2SO4 will react with solid sodium hydroxide NaOH to produce aqueous sodium sulfate Na2SO4 and liquid water H2O . Suppose 31. g of sulfuric acid is mixed with 11.5 g of sodium hydroxide. Calculate the maximum
Upon heating 8.5g sample of Sodium Sulfate hydrate, it loses 4.776 grams after heating. What steps are necessary for me to find the n for the hydrate? GIVEN: Na2SO4 - n H2O the molar mass of sodium sulfate is 142.05g/mol
When aqueous solutions of sodium sulfate and lead (II) nitrate are mixed lead sulfate precipitates out of soultion. Calculate the mass of lead (II) sulfate that should form when 1.25 L of 0.0500 M Pb(NO3)2 and 2.00 L of 0.0250 M
What mass of solution containing 6.50% sodium sulfate N2SO4 by mass contains 1.50g Na2SO4 Set up a proportion. (g Na2SO4/g solution) = (1.50 g Na2SO4/x g solution). Solve for x. Check my work. how do you fine g solution