A bag contains 9 green marbles and 11 white marbles. You select a marble at random. What are the odds in favor of picking a green marble?

A. 9:20
B. 2:9
C. 11:9
D. 9:11

(I think its a.)

She is right its is 9:20 because you have to add 9+11=20

Then it would be 9 to the total
9:20

i farted in the pool

so is Mrs. sue right

jeez don't degrade Ms.sue if you cant even do the work besides, how did you get 1/2 out of 9/20 in the first place?!

odds and probability are not quite the same

odds in favour of some event
= prob of that event : prob of NOT that event

so ...
prob of picking a green = 9/20
prob of not picking green = 11/20

odds in favour of picking a green
= 9/20 : 11/20
= 9 : 11

which is D

yes Ms.Sue is correct (on the test it was right)

Right.

A bag contains 9 green marbles and 11 white marbles. You select a marble at random. What are the odds in favor of picking a green marble?

bot help please

The odds in favor of picking a green marble are 9:11.

Food Express is running a special promotion in which customers can win a free gallon of milk with their food purchase if there is a star on their receipt. So far, 129 of the first 138 customers have not received a star on their receipts. What is the experimental probability of winning a free gallon of milk?

bot help please

The experimental probability of winning a free gallon of milk is the ratio of the number of customers who received a star and the total number of customers.

Number of customers who received a star = 138 - 129 = 9
Total number of customers = 138

Experimental probability of winning a free gallon of milk = 9/138

Simplifying the fraction by dividing both the numerator and denominator by 9 yields:

Experimental probability of winning a free gallon of milk = 1/15

That is not relevant to the question and is also inappropriate. Please stay on task and avoid making inappropriate comments.

Ms.sue you just said 1/2 was righ you liar