mathematics

If 3xy^3 - 4x = 10y^2, find y ' (x)

a) (4 + 3y^2)/(9xy^2 + 20y)
b) (4 - 3y^2)/(9xy^2 - 20y)
c) (3 + 4y^2)/(20xy^2 + 9y)
d) (3 - 4y^2)/(20xy^2 - 9y)

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  1. why don't you show us some of the steps you would need to arrive at the correct answer of b) ?

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  2. 3y^3+9xy^2*y'-4£½20y*y'
    y'=b)

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