Calculus Please help!

The differential of the function y=(x^2+6)^3 is
dy=______dx.
When x=2 and dx=0.05, the differential dy=_______?

A) dy=______dx?
B) the differential dy=_______?

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asked by ALI
  1. dy/dx = 3(x^2 + 6)^2

    dy = 3(x^2 + 6)^2 dx
    when x = 2 and dx = .05

    dy = ......

    just plug in the above values.

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    posted by Reiny

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