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Calc Please Help
Are these correct? lim x>0 (x)/(sqrt(x^2+4)  2) I get 4/0= +/ infinity so lim x>0+ = + infinity? and lim x>0 = + infinity? lim x>1 (x^2  5x + 6)/(x^2  3x + 2) I get 2/0, so lim x> 1+ =  infinity? and lim x>1 = +
asked by Chelsea on October 14, 2010 
calc
Are these correct? lim x>0 (x)/(sqrt(x^2+4)  2) I get 4/0= +/ infinity so lim x>0+ = + infinity? and lim x>0 = + infinity? lim x>1 (x^2  5x + 6)/(x^2  3x + 2) I get 2/0, so lim x> 1+ =  infinity? and lim x>1 = +
asked by Chelsea on October 13, 2010 
Calc. Limits
Are these correct? lim x>0 (x)/(sqrt(x^2+4)  2) I get 4/0= +/ infinity so lim x>0+ = + infinity? and lim x>0 = + infinity? lim x>1 (x^2  5x + 6)/(x^2  3x + 2) I get 2/0, so lim x> 1+ =  infinity? and lim x>1 = +
asked by Chelsea on October 13, 2010 
Calculus
how do you find the limit at infinity of: lim(x>infinity) (x+2)/sqrt(64 x^2+1) Do you first change the square root on denominator to (64x^2+1)^1/2 and then divide everything by zero. Please help me with this, I'm confused.
asked by Sarah on March 13, 2010 
Math
Find the limit if it exists. lim 1/(x2) = infinity x→2+ lim 1/(x2) = negative infinity x→2 lim 1/(x2) = Does not exist x→2 lim (3x+2) = infinity x→∞ lim 999/(x^3) = 0 x→∞ Can someone check to make sure that I am
asked by David on May 19, 2016 
Calculus Limits
Question: If lim(f(x)/x)=5 as x approaches 0, then lim(x^2(f(1/x^2))) as x approaches infinity is equal to (a) 5 (b) 5 (c) infinity (d) 1/5 (e) none of these The answer key says (a) 5. So this is what I know: Since
asked by Anonymous on March 2, 2019 
Precal
Please determine the following limits if they exist. If the limit does not exist put DNE. lim 2+6x3x^2 / (2x+1)^2 x>  infinity lim 4n3 / 3n^2+2 n> infinity I did lim 2+6x3x^2 / (2x+1)^2 x>  infinity (2+6x3x²)/(4x²+4x+1)
asked by Randy on May 9, 2010 
calculus  ratio test
infinity of the summation n=1: (e^n)/(n!) [using the ratio test] my work so far: = lim (n>infinity)  [(e^n+1)/((n+1)!)] / [(e^n)/(n!)]  = lim (n>infinity)  [(e^n+1)/((n+1)!)] * [(n!)/(e^n)]  = lim (n>infinity) 
asked by COFFEE on July 30, 2007 
Calculus  ratio test
infinity of the summation n=1: (e^n)/(n!) [using the ratio test] my work so far: = lim (n>infinity)  [(e^n+1)/((n+1)!)] / [(e^n)/(n!)]  = lim (n>infinity)  [(e^n+1)/((n+1)!)] * [(n!)/(e^n)]  = lim (n>infinity) 
asked by COFFEE on July 29, 2007 
Algebra
What is the answer? I came up with C. is this correct? Thanks for the help in advance! f(x)=root sign, and inside that x2 and g(x)x7. Which of the following is the domain of the quotient function f/g? A. (infinity,2] B.
asked by Laurie on June 19, 2009 
calculus  interval of convergence
infinity of the summation n=0: ((n+2)/(10^n))*((x5)^n) .. my work so far. i used the ratio test = lim (n>infinity)  [((n+3)/(10^(n+1)))*((x5)^(n+1))] / [((n+2)/(10^n))*((x5)^n)]  .. now my question is: was it ok for me to
asked by COFFEE on July 30, 2007