# chemistry

Using a BCA table, calculate the molarity of a 25.0 mL sample of HNO3 that's is titrated to its endpoint with 22.7 mL of 0.200 M NaOH.

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1. HNO3 + NaOH ==> NaNO3 + HOH

You construct the table.
mols NaOH = M x L = ??
The equation tells you it is 1 mol NaOH to 1 mol HNO3; therefore.
mols NaOH = mols HNO3
Then M HNO3 = mols HNO3/L HNO3.
Yo have mols and you have L. Calculate M HNO3.

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2. thanks

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posted by caleb

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