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What would you need to multiply by in order to solve this system of equations using the linear combination (elimination) method? {6x−2y=4 7x+5y=3 Multiply the 1st equation by 3 and leave the 2nd equation alone. This will
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simultaneous equations x + 2y = 4 3x  4y = 7 x=3 and y = 1/2 i need to explain how i got this answer and do not know how to do that? i am confused about how you got this answer what working out is it the object in "elimination"
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To solve the following system of equations by elimination, which step would best to perform first? 1/2a  1/4b = 1 1/3a + b= 3 A. Add the two equations. B. Subtract the two equations. C. Multiply the first equation by 4. D. Divide
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ur supposed to add straight down, but then i think u have to multiply one equation by the other to get y to cancel out, and then i get up to that step, and then just get really confused, i really do appreciate any help...THANX
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You are given two equations which are both true, and you are asked to solve for both x and y. You plan to solve this set of equations by substituting part of one equation into the other so you end up with an equation that contains
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Solve the system of equations using the Addition method. 2a + 3b = 1 3a + 5b = 2 The addition method tells you to find common multiples of a coefficient, then add the equations together to eliminate a variable. If you multiply
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Solve the system of equations: First:x+3y=5 Second:3xy=5 multiply the second equation by 3 then add both equations(I know I have it wrong somewhere I just guessed at the solution and it worked. I got (2,1)
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A student is trying to solve the set of two equations given below: Equation A: x + z = 6 Equation B: 2x + 4z = 1 Which of the following is a possible step used in eliminating the zterm? Multiply equation B by 4. Multiply equation
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I need a step by step explanation on how to add these two equations 2x+3y=1 5x+3y=16 Subtract the first equation from the second. (Subtract left and right sides separately). This gives you 3x = 15 Then divide both sides by 3. x =
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I need help solve the equation by fractions 8/(21y) = 12/(y+19) I think the answer is y = 5, i just need to know how to do work out. i done some solution like this first multiply by(21y)(y+19)(assuming that y = 21 and y = 19:
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