A volume of 5oo ml of potassium sodium tartrate solution S1 of c1=0.21mol/l is to prepared. Determine the mass of hydrated potassium sodium tartrate of formula KNaC4H4O6.4H2O needed for this preparation .(molar atomic masses : H=1;C=12;O=16;Na=23;K=39)
How many mols do you need? That's M x L = ?
Then convert that to grams. mols = grams/molar mass. You can calculate molar mass and you know mols from above, solve for grams.
To determine the mass of hydrated potassium sodium tartrate required for the preparation of the solution, you need to follow these steps:
Step 1: Find the number of moles of potassium sodium tartrate required
The given concentration of the solution (c1) is 0.21 mol/L. The volume (V) of the solution required is 500 mL = 0.5 L. So, the number of moles (n) can be calculated using the equation:
n = c1 * V
Substituting the given values:
n = 0.21 mol/L * 0.5 L = 0.105 mol
Step 2: Calculate the molar mass of hydrated potassium sodium tartrate
The formula for hydrated potassium sodium tartrate is KNaC4H4O6.4H2O. To calculate the molar mass, you need to multiply the atomic masses of each element by the number of atoms present in the formula. The molar masses are as follows:
H: 1 g/mol
C: 12 g/mol
O: 16 g/mol
Na: 23 g/mol
K: 39 g/mol
Calculating the molar mass:
Molar mass of KNaC4H4O6.4H2O = (39 * 1) + (23 * 1) + (4 * 12) + (4 * 1) + (6 * 16) + (4 * (1 * 2) + 16)
= 39 + 23 + 48 + 4 + 96 + (4 * 18)
= 39 + 23 + 48 + 4 + 96 + 72
= 282 g/mol
Step 3: Calculate the mass of hydrated potassium sodium tartrate
Using the equation:
mass = n * molar mass
Substituting the values:
mass = 0.105 mol * 282 g/mol
= 29.61 g
Therefore, the mass of hydrated potassium sodium tartrate (KNaC4H4O6.4H2O) needed for the preparation of the solution is approximately 29.61 grams.