Draw three repeating units of the condensation polymer made from ethanedioic acid and ethanediol.
if anyone has a weblink that illustrates this may you please send it?
Unfortunately, as a text-based AI, I am unable to provide direct visual illustrations or web links. However, I can describe the structure of the repeating units made from ethanedioic acid (also known as oxalic acid) and ethanediol.
When ethanedioic acid reacts with ethanediol through a condensation polymerization process, the resulting polymer is called poly(ethylene oxalate). Here's how the repeating units would look:
1. Start with ethanedioic acid (HOOC-COOH) and ethanediol (HO-CH2-CH2-OH).
2. One molecule of ethanedioic acid reacts with one molecule of ethanediol, leading to the formation of a repeating unit.
3. The esterification reaction occurs between the carboxyl group (COOH) of ethanedioic acid and one hydroxyl group (OH) of ethanediol. This forms a bond known as an ester linkage (-COO-).
4. The remaining carboxyl group (COOH) of the ethanedioic acid can then react with another molecule of ethanediol to continue the polymer chain.
So, the repeating unit of poly(ethylene oxalate) would be:
HOOC-COO-CH2-CH2-OOC-COOH
Please note that the representation above is a simplified version, and in reality, the polymer chain can be much longer with more repeating units.
Additionally, you may find visual illustrations of the structure by searching for "poly(ethylene oxalate)" or "structure of poly(ethylene oxalate)" in search engines or scientific databases.
To draw three repeating units of the condensation polymer made from ethanedioic acid (also known as oxalic acid) and ethanediol (also known as ethylene glycol), you'll need to understand the structure of both monomers and the way they combine during polymerization.
First, let's look at the structures of ethanedioic acid and ethanediol:
- Ethanedioic acid (oxalic acid) has the formula HOOC-COOH. It consists of two carboxylic acid groups (-COOH) attached to a central carbon atom.
- Ethanediol (ethylene glycol) has the formula HO-CH2-CH2-OH. It has two hydroxyl groups (-OH) attached to a two-carbon chain.
During condensation polymerization, the -OH group of ethanediol reacts with the -COOH group of ethanedioic acid, resulting in the elimination of water (H2O) as a byproduct. This reaction forms an ester linkage between the two monomers.
To draw the repeating units:
1. Start by drawing the structure of ethanedioic acid (HOOC-COOH), and label it as the "acid" component.
2. Next, draw the structure of ethanediol (HO-CH2-CH2-OH) and label it as the "alcohol" component.
3. Connect the acid and alcohol components by removing one hydroxyl group (-OH) from ethanediol and one carboxylic acid group (-COOH) from ethanedioic acid.
4. Join the remaining -OH group of ethanediol with the remaining -COOH group of ethanedioic acid, while eliminating a molecule of water (H2O). This forms the ester linkage between the two monomers.
5. Repeat the process to create a chain of repeating units. Each monomer will lose one -OH group and one -COOH group in the reaction, forming an alternating repeating unit.
Unfortunately, as an AI text-based tool, I cannot send or access specific web links. However, you can search for "polymerization of ethanedioic acid and ethanediol" or "condensation polymer of oxalic acid and ethylene glycol" in search engines to find diagrams and visual representations of the repeating units.
Remember to cross-check different sources and select reliable ones such as scientific publications, educational websites, or chemistry textbooks to ensure accuracy.