Chemistry

A+2B--->2C Kc=2.27
2c--->D Kc=0.144

Calculate the equilibrium constant for the reaction
D--->A+2B

asked by Meredith
  1. Add eqn 1 to eqn 2 to obtain
    A+2B ==> 2C
    2C ==> D
    ------------
    A + 2B ==> D so K' = k1*k2.
    You want the reverse of this rxn; therefore, you want 1/K'.

    posted by DrBob222

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