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A ball is thrown straight up. Its height, h(in metres), after t seconds is given by h=5t^2+10t+2. To the nearest tenth of a second, when is the ball 6m above the ground? Explain why there are two answers. I don't get how to
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A ball is thrown straight up. Its height, h(in metres), after t seconds is given by h=5t^2+10t+2. To the nearest tenth of a second, when is the ball 6m above the ground? Explain why there are two answers. you have to equate h to
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A ball is thrown straight up. Its height, h(in metres), after t seconds is given by h=5t^2+10t+2. To the nearest tenth of a second, when is the ball 6m above the ground? Explain why there are two answers. I don't get how to
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