Algebra

On an 18-hole golf course, there are par-3 holes, par-4 holes, and par-5 holes. A golfer who shoots par on every hole has a total of 66. There are twice as many par-4 holes as there are par-5 holes. How many of each type of hole are there on the golf course?

How many par-3 holes are there__?
How many par-4 holes are there__?
How many par-5 holes are there__?

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  1. let there b x par-3, y par-4, z par-5 holes. Then

    x+y+z = 18
    3x+4y+5z = 66
    y = 2z

    Now just solve for x,y,z

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  2. I'm not sure if I did this right, but I followed your formula, and got 9,6, and 3 as the answer. Is this correct?

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