C6H14 + Cl2 in UV light
Below are 5 products, say which one cannot be a product, prove this by showing how each of the other products were formed from the equation above.
1-chlorohexane
2-chlorohexane
2,2-dichlorohexane
dodecane
hex-1-ene
Ava. I'm not an organic chemist and I don't know the answer. I googled
"free radical halogenation of alkanes" and came up with this. It may or may not help.
http://en.wikipedia.org/wiki/Free-radical_halogenation
I do not know who provided you the names, but 1-chlorohexane is not valid: it should just be Chlorohexane. Chlorohexane and dodecane are the two primary products from the termination step in free radical halogenation, as well as HCl, therefore you can rule those two answers out. It is plausible to produce a mono-substituted product, so I would have to say that you can get a di-substituted product. But I have never heard of an alkene being produce from a radical halogenation reaction. Therefore, I will go with hex-1-ene as the correct answer choice. I can not post a link but, I believe that you can google the mechanism to show how all of the products will be produced.
It did help. Thank you very much :-)
To determine which product cannot be formed from the given reaction of C6H14 + Cl2 in UV light, we need to assess the possible products and analyze how they are formed. Let's go through each of the products mentioned:
1. Chlorohexane (C6H13Cl): This product can be formed by the substitution reaction between hexane (C6H14) and one chlorine atom from Cl2. The chlorine atom substitutes for one hydrogen atom in hexane, yielding chlorohexane.
2. 2-Chlorohexane (C6H13Cl): This product can also be formed by the same substitution reaction as described above. The only difference is that the chlorine atom substitutes for a different hydrogen atom in the hexane molecule, resulting in a different positional isomer.
3. 2,2-Dichlorohexane (C6H12Cl2): This product can be formed when two chlorine atoms from Cl2 each substitute for one hydrogen atom in the hexane molecule. Both chlorine atoms attach to the same carbon atom, resulting in a dichlorinated compound.
4. Dodecane (C12H26): Dodecane cannot be formed from the given reaction since it is not a chlorinated compound. The reaction between C6H14 and Cl2 in UV light only allows for the substitution of chlorine atoms, not hydrocarbon chains.
5. Hex-1-ene (C6H12): Hex-1-ene cannot be obtained from the given reaction either because it involves the elimination of hydrogen atoms rather than the substitution of chlorine atoms. The reaction of C6H14 and Cl2 in UV light does not facilitate the formation of alkenes.
To summarize, dodecane and hex-1-ene cannot be products of the given reaction of C6H14 + Cl2 in UV light. Dodecane cannot be formed because it is not a chlorinated compound, and hex-1-ene cannot be formed because it involves the elimination of hydrogen atoms rather than substitution reactions.